Specific Heat of Water Calculator
| Temperature (°C) | Specific Heat (J/g°C) |
|---|---|
| 0 | 4.217 |
| 10 | 4.182 |
| 20 | 4.179 |
| 30 | 4.191 |
| 40 | 4.214 |
| 50 | 4.238 |
| Temperature (°C) | Specific Heat Capacity (J/(g°C)) |
|---|---|
| 0 | 4.219 |
| 10 | 4.182 |
| 20 | 4.179 |
| 30 | 4.191 |
| 40 | 4.214 |
| 50 | 4.244 |
| 60 | 4.278 |
| 70 | 4.317 |
| 80 | 4.360 |
| 90 | 4.407 |
| 100 | 4.359 |
| 110 | 4.416 |
| 120 | 4.477 |
| 130 | 4.543 |
| 140 | 4.614 |
| 150 | 4.690 |
FAQs
1. How do you calculate the specific heat capacity of water at different temperatures?
The specific heat capacity (c) of water at different temperatures can be determined experimentally by measuring the amount of heat (Q) required to change the temperature (ΔT) of a given mass (m) of water. The formula for specific heat capacity is:
c = Q / (m * ΔT)
2. What is the heat capacity of water at different temps?
The heat capacity of water varies with temperature. It is the amount of heat required to raise the temperature of a given amount of water by one degree Celsius or Kelvin. The specific heat capacity of water is approximately 4.184 J/(g°C) at around 25°C.
3. What is the CP of water at 25°C?
The specific heat capacity of water (CP) at 25°C is approximately 4.184 J/(g°C).
4. What formula is Q = MCΔT?
The formula Q = MCΔT represents the amount of heat (Q) absorbed or released when a mass (M) of a substance undergoes a temperature change (ΔT). Here, C represents the specific heat capacity of the substance.
5. How do you find specific heat capacity with temperature change?
To find the specific heat capacity of a substance with a temperature change, you need to measure the amount of heat absorbed or released (Q) during the temperature change, and the mass (m) of the substance. Then, use the formula:
c = Q / (m * ΔT)
6. How do you calculate heat capacity from temperature change?
Heat capacity (C) is calculated from the specific heat capacity (c) of a substance and the mass (m) of the substance. The formula is:
C = m * c
7. How do you calculate specific heat capacity?
Specific heat capacity (c) is calculated by measuring the amount of heat (Q) required to change the temperature (ΔT) of a given mass (m) of a substance using the formula:
c = Q / (m * ΔT)
8. Does CP change with temperature?
In general, the specific heat capacity (CP) of substances can vary with temperature, especially for gases. For water, the specific heat capacity does not change significantly over a small range of temperatures.
9. Is the specific heat of water 4.184 J?
Yes, the specific heat capacity of water is approximately 4.184 joules per gram-degree Celsius (J/(g°C)).
10. What is the CP of water at 20 degrees?
The specific heat capacity (CP) of water at 20 degrees Celsius is approximately 4.179 J/(g°C).
11. What is the CP of water at 40°C?
The specific heat capacity (CP) of water at 40 degrees Celsius is approximately 4.214 J/(g°C).
12. What is the specific heat capacity of water at 30 degrees Celsius?
The specific heat capacity of water at 30 degrees Celsius is approximately 4.191 J/(g°C).
13. How do you solve specific heat problems?
To solve specific heat problems, you need to know the mass of the substance, the initial and final temperatures, and the amount of heat exchanged. Use the formula c = Q / (m * ΔT) to calculate the specific heat capacity.
14. What is the formula for the specific heat conversion?
There is no specific formula for “specific heat conversion.” Specific heat is a property of a substance and is generally given in J/(g°C) or J/(kg°C), depending on the unit of mass used.
15. How do you calculate heat absorbed by water?
To calculate the heat absorbed by water, use the formula:
Q = m * c * ΔT
where: Q = heat absorbed (in joules) m = mass of water (in grams) c = specific heat capacity of water (approx. 4.184 J/(g°C)) ΔT = change in temperature (final temperature – initial temperature)
16. What is the formula of specific heat at constant temperature?
The formula for specific heat at constant temperature is the same as the general formula for specific heat capacity:
c = Q / (m * ΔT)
17. What is the formula for calculating specific heat capacity of any material?
The formula for calculating the specific heat capacity of any material is:
c = Q / (m * ΔT)
where: c = specific heat capacity (in J/(g°C)) Q = heat exchanged (in joules) m = mass of the material (in grams) ΔT = change in temperature (final temperature – initial temperature)
18. How is heat capacity related to temperature?
Heat capacity is related to temperature in that it represents the amount of heat energy required to raise the temperature of a given substance. The heat capacity of a substance is directly proportional to its mass and specific heat capacity, and it increases as the temperature range over which it is measured increases.
19. How does temperature affect the specific heat ratio?
The specific heat ratio, also known as the adiabatic index (γ), is a thermodynamic property that relates the specific heat capacities at constant pressure (CP) and constant volume (CV) of a gas. For ideal gases, the specific heat ratio is constant and does not change with temperature.
20. How are the amount of heat transferred and the change in temperature of water related?
The amount of heat transferred (Q) to or from water is directly proportional to the change in temperature (ΔT) experienced by the water, given a constant mass. The relationship is represented by the equation:
Q = m * c * ΔT
where m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
21. What is the specific heat capacity of water at 1 degree Celsius?
The specific heat capacity of water at 1 degree Celsius is approximately 4.186 J/(g°C).
22. Is the specific heat of water 4.2 joules?
The specific heat of water is approximately 4.184 joules per gram-degree Celsius (J/(g°C)). The value is close to 4.2 joules but slightly different.
23. What is the physics specific heat of water?
The specific heat of water in physics is approximately 4.184 joules per gram-degree Celsius (J/(g°C)). It is commonly used in physics and other scientific fields for heat-related calculations.
24. What is the CP of water at 15°C?
The specific heat capacity (CP) of water at 15 degrees Celsius is approximately 4.190 J/(g°C).
25. What is the specific heat capacity of water at 23 degrees Celsius?
The specific heat capacity of water at 23 degrees Celsius is approximately 4.182 J/(g°C).
26. What is the specific heat capacity of water at 37 degrees Celsius?
The specific heat capacity of water at 37 degrees Celsius is approximately 4.168 J/(g°C).
27. What state is pure water at 50°C?
At 50°C, pure water is in a liquid state.
28. What is water at 50°C?
Water at 50°C is in the liquid state.
29. What is the specific heat capacity of water at 90°C?
The specific heat capacity of water at 90 degrees Celsius is approximately 4.152 J/(g°C).
30. How much heat is needed to raise the temperature of 100g of water 50°C?
The amount of heat needed to raise the temperature of 100g of water by 50°C can be calculated using the formula Q = m * c * ΔT:
Q = 100g * 4.184 J/(g°C) * 50°C Q = 20920 joules
31. Is specific heat the same as heat capacity?
No, specific heat and heat capacity are related but not the same. Specific heat (c) is the amount of heat energy required to raise the temperature of a given mass of a substance by one degree Celsius. Heat capacity (C) is the total amount of heat energy required to raise the temperature of an entire object or substance by one degree Celsius. The heat capacity is equal to the product of the specific heat and the mass of the substance (C = m * c).
32. How hot is 70 degrees Celsius water?
Water at 70 degrees Celsius is quite hot and can cause burns or scalds on the skin.
33. How much heat is required to convert 30 grams of water at 100 degrees Celsius into steam?
To convert 30 grams of water at 100 degrees Celsius into steam, you need to calculate the heat required for the phase change (latent heat of vaporization) and the heat required to raise the temperature from 100°C to the boiling point. The specific heat of water is used for the latter part of the calculation.
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